The statement sim (p leftrightarrow sim q) is | vedclass

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(A) To determine the equivalence,we construct the truth table for the given expression $\sim (p \leftrightarrow \sim q)$ and compare it with the truth

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Equivalent to $p \leftrightarrow q$

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(A) To determine the equivalence,we construct the truth table for the given expression $\sim (p \leftrightarrow \sim q)$ and compare it with the truth table for $p \leftrightarrow q$.      $p$    $q$    $\sim q$    $p \leftrightarrow \sim q$    $\sim (p \leftrightarrow \sim q)$    $p \leftrightarrow q$        $T$    $T$    $F$    $F$    $T$    $T$        $T$    $F$    $T$    $T$    $F$    $F$        $F$    $T$    $F$    $T$    $F$    $F$        $F$    $F$    $T$    $F$    $T$    $T$  From the truth table,the column for $\sim (p \leftrightarrow \sim q)$ is identical to the column for $p \leftrightarrow q$. Therefore,the statement is equivalent to $p \leftrightarrow q$.

The statement $\sim (p \leftrightarrow \sim q)$ is

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